-2.5+9.3(T)+10(t)^2=0

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Solution for -2.5+9.3(T)+10(t)^2=0 equation: 



-2.5+9.3()+10(T)^2=0

We add all the numbers together, and all the variables

10T^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$T=\frac{-b}{2a}=\frac{0}{20}=0$

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